A rope of length L that weighs 1/2 lb/ft is lying on the ground. What is the work done in lifting the rope so that it hangs from a beam 2L feet high?

Question

ageta · Answer

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yb1996 · Answer

What is that supposed to be?

irishboy123 · Answer

you should provide more data. 

how is it left hanging?

maybe draw it :p

yb1996 · Answer

That's all the information that I'm given. I'm assuming that the whole rope is pulled up a length of 2L.

yb1996 · Answer

Is this how the equation should be set up?

$$\int\limits_{0}^{2L}0.5(2L-L)dL$$

yb1996 · Answer

I just got more information. The whole rope is pulled up to a bar to the point where one tip of the rope is on the bar and the rest of the rope is hanging.

yb1996 · Answer

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yb1996 · Answer

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ageta · Answer

use work is =force time distance

yb1996 · Answer

yeah, but the weight of the rope will be changing as you pull the rope up from the floor, which means the force will not be constant throughout.