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Factor and solve a^3n -b^3n
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is it \[a ^{3n}\]
a^n-b^n(a^2n+b^2n+a^nb^n)
I'm completely lost....... I don't understand :( sorry
ok we know that a^3-b^3=(a-b)(a^2+b^2+ab)
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instead of a we are using a^n
So I use sum or difference of cubes?
difference of cubes
also if (a^n)^2=a^2n we multiply the powers
\[a^n-b^n(a^2n+b^2n+a^nb^n)\] this general idea, just to make it clear is not like this \[a^n-b^n(a2n+b2n+anbn)\]
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I got the same answer as you @Andresfon12
@Maddiem is it \[a ^{3n}\]
yes
so as i have done it above is the right procedure
that just a general formula he @ kanwal32 gave you, no the answer
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OKay! thanks guys for the help :D
np
welcome
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