HELP!!! WILL FAN AND MEDAL!!!!
Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ball B has a mass of 3 kilograms. The initial velocity of ball A is 9 meters per second to the right, and the initial velocity of the ball B is 6 meters per second to the left. The final velocity of ball A is 9 meters per second to the left, while the final velocity of ball B is 6 meters per second to the right.
1. Explain what happens to each ball after the collision. Why do you think this occurs? Which of Newton’s laws does this represent?
@escamer
@rarecigs
Is this easy enough?
From what i know now. It represents Newton's third law which states "For every action there is an equal and opposite reaction" im not to sure about the rest :/
thanks thats the part i was stuck on
not a problem. Glad i could help
=D
@comrad
well?
@jabez177
@imqwerty please help me
jabez said your good at physics qwerty so i asked you =)
......??
Thank you soooooooooooooooooooo much for this really long answer.....
alright so here newton's 3rd law comes into play it says that when 2 bodies collide they exert equal and opposite force on each other so if the ball A exerts force \(F_1\) and ball B exerts force \(F_2\) then \(F_1=-F_2\) here we put that negative sign because both forces are opposite to each other the forces act between the two objects for a given amount of time. In some cases, the time is long; in other cases the time is short. Regardless of how long the time is, it can be said that the time that the force acts upon object 1 is equal to the time that the force acts upon object 2. This is merely logical. so \(t_1=t_2\) Since the forces between the two objects are equal in magnitude and opposite in direction, and since the times for which these forces act are equal in magnitude, it follows that the impulses experienced by the two objects are also equal in magnitude and opposite in direction. As an equation, this can be stated as \(F_1 \times t_1= -F_2 \times t_2\) => \(m_1 \Delta v_1= - m_2 \Delta v_2\) here \(v_1\) and \(v_2\) denote the velocities of ball A and B resectively and \(\Delta v_1\) is nothing but this-> change in velocity of ball A and \(\Delta v_2\) is nothing but this-> change in velocity of ball B change in velocity in nothing but -> final velocity - initial velocity using this logic you can prove the given statement as alright helpful link- http://www.physicsclassroom.com/class/momentum/Lesson-2/Momentum-Conservation-Principle
O...M.....G 0_0 thank you sooooo much
yw
in short you can say this-> the two balls come and collide and revert back from where they came after collision and this occurs because both balls exert force on each other when they collide. this is newton's third law
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