Write the equation for a circle with the following characteristics: -the center is on the line whose equation is 3y+12=2x -is tangent to both the x and y axis Only an algebraic solution will be accepted
y=2/3x-4 is the standard form of the equation for the line
so the circle passes though the points (0,y1) and (x1,0) and its centre is at ( (2/3x2 - 4, y2)
i graphed the line and it crosses through points (0,6) and (-4,0)
that means the center is (-3,2) i believe. i dont know how to do that algebraically though
right and the radius is also equal to y2
how could i show this algebraically
( x - (2/3 x2 - 4)^2 + (y - r)^2 = r^2
this is an interesting one but i haven't got my head around it yet. Unfortunately i have to go right now. sorry
ok thanks
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