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Find the amplitude y = -5 sin 1/2x
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pffft... is that hmmm come on now, the amplitude is right in front of your nose
Seriously, though, just read the number off the front. Ignore the sign.
I hope you do realize that the amplitude is in the equation already.
\(\large y=-{\color{blue}{ 5}}sin\left( \frac{1}{2}x \right)\qquad {\color{blue}{ amplitude}}\)
I didn't know if it was -5 or 5... Thank you guys
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the amplitude is, the absolute value of whatever that number in fron is so in this case | -5 | = 5
Amplitude cannot be negative. It is just a representation of how far from the midline it is..
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