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OpenStudy (matlee):
OpenStudy (matlee):
I know the answer althoguh i dont know the steps to get there
Directrix (directrix):
What did you get for the answer? @matlee
OpenStudy (matlee):
-2
OpenStudy (matlee):
i just noticed all i had to do is plug 2 into x?
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OpenStudy (matlee):
was that it
Directrix (directrix):
If f(x) = -5 when x = 2, then what is the limit of f(x) as x approaches 2.
OpenStudy (matlee):
For some reason i dont understand the term as x approaches 2
OpenStudy (matlee):
so wait when i enter 2 into x i get -2 is that how im suppose to do it but i dont know how to get -5
Directrix (directrix):
That is the x-->2 underneath lim at the beginning of the problem.
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OpenStudy (matlee):
Oh ok thank you, but does it mean like since it approaches 2 it also passes (1) so the answer to X could also be 1?
Directrix (directrix):
Look at the problem.
f(x) = - x^2 + 2 given that x is NOT equal to 2. So, you cannot put 2 in there and crank out -2 as a point of graph of f(x) = - x^2 + 2 .
Directrix (directrix):
The second piece of the definition of f(x) tells you that when x = 2, then f(2) equals what?
OpenStudy (matlee):
5
OpenStudy (matlee):
-5
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