Question

The equation of the circle whose center is at (2, 1) and radius is 3 is
(x + 2)² + (y + 1)² = 9
(x - 2)² + (y - 1)² = 9
(x - 2)² + (y - 1)² = 3

Answer 1

the equation of the circle whose center is (h,k) =(2 ,1) and radius r= 3 is

\[(x-h)^{2}+(y-k)^{2} = r ^{2}\]
substitute the values

Answer 2

so do i just put the values in?

Answer 3

yes

Answer 4

so what would i put in for x and y?

Answer 5

nothing
u have to replace h,k and r

Answer 6

so x-2^2+y-1^2=3?

Answer 7

u must put brackets
what about r^2

Answer 8

ok i got it thanks