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Image below If RB = 4 and OR = 3, then OB = 5 7 2√3 I would like to know how to solve it.
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I think it's 5 but I'm not sure if that's correct.
give me a minute
Okay
@AloneS
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hey alone do you think you can help with the question
?
@mathmale do you think you can help me?
@SolomonZelman
\[OR^2+RB^2=OB^2.\] So \[4^2+3^2\overset{?}{=}5^2\]
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Okay I get it now. Thank you.
7 is incorrect
\[4^2+3^2=16+9=25=5^2\]
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