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Mathematics 19 Online
OpenStudy (tygrr321):

plz help me asap

OpenStudy (tygrr321):

OpenStudy (anonymous):

i would say B because you can probably only have 1 i hope i helped ☺

OpenStudy (tygrr321):

ok thx let me see wat other people say to

OpenStudy (anonymous):

2m +4(m-3)=7m-4 or, 2m+4m-12=7m-4 or, 6m-7m=-4+12 or, -m = -8 or, m=8

OpenStudy (anonymous):

So we only get one solution @tygrr321

OpenStudy (tygrr321):

thank you so much

OpenStudy (anonymous):

anytime :)

OpenStudy (tygrr321):

have time for a few more? @Learner11

OpenStudy (anonymous):

sure :)

OpenStudy (tygrr321):

OpenStudy (tygrr321):

hello?

OpenStudy (anonymous):

|dw:1455218032838:dw| sorry for late reply

OpenStudy (anonymous):

Now put the values of a and b and check the answers

OpenStudy (tygrr321):

im confused

OpenStudy (anonymous):

take the values from a and b from each option and then put this value on the equation \[x = (7+b)/(9-a)\] one value should be fulfill the condition

OpenStudy (tygrr321):

oh ok gimme a sec

OpenStudy (anonymous):

the answer may be more than one . Find them out

OpenStudy (tygrr321):

yes it is multiple choice

OpenStudy (anonymous):

have u find them out?

OpenStudy (tygrr321):

well im confused again i did x=7+b/9-a i placed the numbers in the a and b spots and added and subtracted them depending on if they r in the a or b spot so now i have a bunch of numbers

OpenStudy (anonymous):

if denominator is non-zero then there is unique solution, otherwise , if numerator is 0 to then infinite solution, if numerator not equal to 0 then no soluton

OpenStudy (anonymous):

The answers are A,B,D and E . Only C is wrong

OpenStudy (anonymous):

so if \[9-a \neq 0, \ then \ one \ solution \\ otherwise\ 9 - a = 0, \\ 7 + b = 0 \ then \ infinite \ solution \ else\ 7 + b \neq 0 \ then\ no \ solution\]

OpenStudy (anonymous):

it is b - 7 , not b + 7

OpenStudy (anonymous):

I have to go bye guys . :) and @baljeet16 is going sooo well , @tygrr321, follow him . I will give @baljeet16 a medal . Keep it up

OpenStudy (tygrr321):

ok bye

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