i need help badly

Question

i need help badly

tygrr321 · Answer

attachment

tygrr321 · Answer

the equation is 4x−5(2x+1)=ax+b.

tygrr321 · Answer

@YoungStudier

jdoe0001 · Answer

so..hmm  what did you get?

I mean, notice a = 6, and b= 1
so the equation boils down to $\bf 4x−5(2x+1)=6x+b1$

what did you get?

tygrr321 · Answer

6x+1
6x-4
-6x-5
14x-5

tygrr321 · Answer

lol i was answering someone elses question but they just deleted it
@jdoe0001 i dont have a answer

jdoe0001 · Answer

hmmm $\bf \bf 4x−5(2x+1)=6x+1$ rather... anyhow, simplify  the LHS

tygrr321 · Answer

oh wait the first answer is 6x+1?

jdoe0001 · Answer

hmm how did you get 6x+1 though?

tygrr321 · Answer

by simplifying

jdoe0001 · Answer

ok... so.. what would -5(2x+1) expand to then?

tygrr321 · Answer

-10x-5
@jdoe0001

jdoe0001 · Answer

yeap, thus
4x - 10x = -6x
thus
-6x - 5  for the LHS

tygrr321 · Answer

oh

tygrr321 · Answer

wat about the next parts?

jdoe0001 · Answer

well, you now have
-6x-5 = 6x+1

add 6x to both

-6x+6x-5 = 6x+6x+1
-5 = 12x+1

subtract -1 from both
-1 -5 = 12x+1-1
-6 = 12x

divide both by 12
-6/12 = 12x/12
-6/12 = x
-1/2 = x

tygrr321 · Answer

oh i see...

tygrr321 · Answer

wat about the next part it says "This means that the equation is true for all  number(s).
                                                                                                        one
                                                                                                          or
                                                                                                          no