Question

@dan815

Answer 1

\[\int\limits_{}^{} x \sin^{-1} x dx\]

+ Integrate

\[\int\limits_{}^{} x -2 + \frac{ 1 }{x + 2} dx\]

Answer 2

whats the integral of sin^-1(x)?

Answer 3

never heard of it xD

Answer 4

But I can find it using partial integration. (I think)

Answer 5

http://prntscr.com/a23x6l

Answer 6

so

dv = sin^-1 x dx , u = x

v = sqrt(1-x^2) + xsin^-1x du = dx


integration = x[ sqrt(1-x^2) + xsin^-1x) + integration of (1-x^2) + integration of xsin^-1x

Answer 7

and integration of x sin^-1x with respect to x is in both sides so we have zero -,- = so thing.

Answer 8

Ok, then integrate the second problem.

Answer 9

@dan815 , you didn't integrate -,-