Can someone please help me solve this one problem? I'll definitely give a medal. Solve the system for y=8x-1 and 2x-16y=3
@ganeshie8 @dan815
Are you thinking of using substitution?
Yes the substitution method is fine, but how do I do that for this problem?
You know what y equals, so way not substitute that into the second equation?
Since you know that \(\Large{y=8x-1}\) We can substitue it for the other equation... \(\Large\color{purple}{2x-16(8x-1)=3}\)...You then simplify to get x...
\[2x-16(8x-1)=3\]
Then expand
so would it be -126x=48?..
Or is that wrong.
Shuffle the equation little bit 8x - y = 1, 2x - 16y = 3 multil|dw:1455249579686:dw| |dw:1455249682801:dw| |dw:1455249761525:dw| Similary use this value to solve for x by putting in first equation.
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