Can someone please help me solve this one problem? I'll definitely give a medal.
Solve the system for y=8x-1 and 2x-16y=3
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OpenStudy (savannah_noelle):
@ganeshie8 @dan815
OpenStudy (anonymous):
Are you thinking of using substitution?
OpenStudy (savannah_noelle):
Yes the substitution method is fine, but how do I do that for this problem?
OpenStudy (anonymous):
You know what y equals, so way not substitute that into the second equation?
563blackghost (563blackghost):
Since you know that \(\Large{y=8x-1}\) We can substitue it for the other equation...
\(\Large\color{purple}{2x-16(8x-1)=3}\)...You then simplify to get x...
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OpenStudy (anonymous):
\[2x-16(8x-1)=3\]
OpenStudy (anonymous):
Then expand
OpenStudy (savannah_noelle):
so would it be -126x=48?..
OpenStudy (savannah_noelle):
Or is that wrong.
OpenStudy (anonymous):
Shuffle the equation little bit
8x - y = 1, 2x - 16y = 3
multil|dw:1455249579686:dw|
|dw:1455249682801:dw|
|dw:1455249761525:dw|
Similary use this value to solve for x by putting in first equation.