Question

A question

Answer 1

what do you think

Answer 2

i got 2:3

Answer 3

how u got 2:3

Answer 4

so milk and water has ratio 3/2 - this mean that there are 3 milk and 2 water



3/2 = 1,5 increased by 10% milk

1,5 ----- 100%
x ------- 10%
--------------

x = 1,5 *10/100 = 0,15

so this ratio 1,5 increased by 10% will be equal 1,65

but because the milk percent was increased by 10% so than

3 ----- 100%
x ------ 10%
--------------

x = 3*10/100 = 0,3

so this result that the ratio will be 3,3/2 what mean 3,3 milk and 2 water

hope this will help you

Answer 5

is the answer 7/4

Answer 6

and is this 1,5

1 coma 5 or
1 dot 5

Answer 7

is it 33/20

Answer 8

@agent0smith so exactly what i have wrote above - very nice

Answer 9

u mean answer is 33/20

Answer 10

@jhonyy9 yours was unnecessarily long and hard to read. I assumed the asker knew how to find 10% of 3.

Answer 11

0.3

Answer 12

here is my reasoning:
the initial volume \(V_i\) of solution, is given by this formula:
\[\Large {V_i} = {v_m} + {v_w},\quad {v_m} = \frac{3}{2}{v_w}\]
where \(v_m\) and \(v_w\) are the volumes of the milk and water respectively

Answer 13

Oh I see, the volume of the whole solution is increased by 10% by adding milk, it's not the volume of milk that is increased by 10%.

Answer 14

You can still do it with ratios. The ratio was 3 : 2, so total volume is 5.

So 0.5 was added,10% of the total 5. It was all milk.

So new ratio is 3.5 : 2

Answer 15

@nikolai11111

Answer 16

hi

Answer 17

i needhelp

Answer 18

tag me there

Answer 19

where

Answer 20

where is your question

Answer 21

ok

Answer 22

\[3+\sqrt{x+19-}\sqrt{2} when x =6\]

Answer 23

@nikolai11111 please rewrite your exercise on the open question column - ok. ?

Answer 24

idk how to do that

Answer 25

now, the final volume \(V_f\), of such solution, is:
\[\Large {V_f} = {V_i} + 0.1{V_i} = 1.1{V_i}\]
furthermore, we can write:
\[\Large v{'_m} = kv{'_w}\]
where \(k\) is the coefficient which has to be determined
Developing the formula for \(V_f\), we get:
\[\Large v{'_m} + v{'_w} = 1.1{V_i} = 1.1\left( {{v_m} + {v_w}} \right)\]
where \(v'_m\) and \(v'_w\) are the volumes of milk and water after the dilution. Now, we have:
\[\Large v{'_w} = {v_w},\quad v{'_m} = kv{'_w} = k{v_w}\]
since the volume of water is unchanged
Next, we make some substitutions:
\[\Large k{v_w} + {v_w} = 1.1\left( {\frac{3}{2}{v_w} + {v_w}} \right)\]
from which I get:
\[\Large k = \frac{7}{4}\]

Answer 26

jhon are u there

Answer 27

thnx

Answer 28

:)

Answer 29

:)

Answer 30

@mathmath333 and @michele_laino it is far easier to just use ratios :)

Answer 31

yes! that's right!

Answer 32

michele can u help me

Answer 33

@mathmath333 if you missed it, this is how to do it using ratios:

The milk:water ratio was 3 : 2, so the total volume is 5.

0.5 was added, 10% of the total volume. It was all milk.

So the new ratio is 3.5 : 2

Then just simplify that by doubling both sides.

Answer 34

yes that is easy