Pre-Calculus. Max/min http://prntscr.com/a2yng7
I'll try doing it on my graphing calculator, but I got this wrong before so I'd like to check before I submit anything lol
*graphing calculator too small to show anything* = =; *reopens desmo*
25 mph is correct :)
O: IT IS?
Wha- I don't even remember how I got that. I should just redo it just to commit to memory haha
Oh yeah... I got it off Wolfram because my idjit calculator can't show the graph properly = =;
hmm now i checked. It's little ambiguous. Because at s = 25, we have N(s) = 73.333... and we can't have 73 1/3 cars, right lol
So we can check for intersections of N(s) and N = 73
Since 73 is greatest whole number under 73.333...
Yeah, I thought so too but it was the closest I got to an answer ; ;
kse s
soryyyyyyyyyy some thing i ssss wrong with my keyboaaaard
Zoom in intensively close to maximum point lol Did it for you: https://www.desmos.com/calculator/mzthdcikhz
Then you can check for intersections.
Uh I don't know what to do with this @ @ the graph is just sitting here in front of my face lol
You can click on line then gray dots will show up and then you can click on these dots to display point coordinates
I'm guessing I find the midpoint of these guys? Lol
Ya, therefore answers are 22.722 and 27.506 I think you should put both as answer. This part is ambiguous.
Oh but... it says only one #, not "separate answers by commas" which it usually says for questions with more than one answer
Yeah, again this part is ambiguous. In that case, I would go with 25 lol.
I believe 22.722 and 27.506 are correct answer, but i guess writer of this question didn't double-check or something lol.
So what you got?
Ah, my mother is nagging and using savage curse words at me :')
I think I'll stick with 25 first, check what it says :p
O: IT WAS RIGHT
lol ok
That's really odd. I don't get the logic behind this either. o_O
It's less than highest speed, so technically it is correct lol
Oh, alright o:
Thank you for your help ! ♥ ^-^
yeah math online homework sucks. I've seen many cases like this :/
No problem
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