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Mathematics 16 Online
OpenStudy (candy13106):

Simplify the expression

OpenStudy (candy13106):

Square root of 3 Times Square root of 27

OpenStudy (isaidavila):

√3*√27 Both have the same root so de cam put both in one root √(3*27) √81 Solve that

OpenStudy (candy13106):

9 times 9 so it's 3 to the square root of 3

OpenStudy (isaidavila):

It will be 9

OpenStudy (candy13106):

Can u plz explain

OpenStudy (isaidavila):

√3 and √27 have the same root, yes?

OpenStudy (candy13106):

So the square root of 9

OpenStudy (isaidavila):

So we can put both numbers in one root √(3*27) That is √81= 9 Got it?

OpenStudy (candy13106):

Yea thanks

OpenStudy (candy13106):

Can u help me with 1 more

OpenStudy (isaidavila):

Ok

OpenStudy (candy13106):

5 the square root of 24

OpenStudy (candy13106):

Times 3 the square root of 10

OpenStudy (isaidavila):

5*√24?

OpenStudy (candy13106):

Like the 5 beside the square root of 24

OpenStudy (isaidavila):

5 times √24?

OpenStudy (isaidavila):

5√24

OpenStudy (candy13106):

Times 3 beside the square root of 10

OpenStudy (candy13106):

Yea

OpenStudy (isaidavila):

5√24 times 3√10

OpenStudy (candy13106):

Yea

OpenStudy (isaidavila):

We can separate that like this 5*√24*3*√10

OpenStudy (candy13106):

K

OpenStudy (isaidavila):

(5*3)*(√(24*10)) we put 24 and 10 in the same root

OpenStudy (isaidavila):

15√240

OpenStudy (candy13106):

K

OpenStudy (candy13106):

So is that it?

OpenStudy (isaidavila):

But 240=(2^4)*15 So √(2^4)*15 √16*√15 4√15

OpenStudy (isaidavila):

15*4√15 60√15

OpenStudy (candy13106):

Thanks

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