Mathematics
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OpenStudy (candy13106):
Simplify the expression
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OpenStudy (candy13106):
Square root of 3 Times Square root of 27
OpenStudy (isaidavila):
√3*√27
Both have the same root so de cam put both in one root
√(3*27)
√81
Solve that
OpenStudy (candy13106):
9 times 9 so it's 3 to the square root of 3
OpenStudy (isaidavila):
It will be 9
OpenStudy (candy13106):
Can u plz explain
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OpenStudy (isaidavila):
√3 and √27 have the same root, yes?
OpenStudy (candy13106):
So the square root of 9
OpenStudy (isaidavila):
So we can put both numbers in one root
√(3*27)
That is
√81= 9
Got it?
OpenStudy (candy13106):
Yea thanks
OpenStudy (candy13106):
Can u help me with 1 more
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OpenStudy (isaidavila):
Ok
OpenStudy (candy13106):
5 the square root of 24
OpenStudy (candy13106):
Times 3 the square root of 10
OpenStudy (isaidavila):
5*√24?
OpenStudy (candy13106):
Like the 5 beside the square root of 24
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OpenStudy (isaidavila):
5 times √24?
OpenStudy (isaidavila):
5√24
OpenStudy (candy13106):
Times 3 beside the square root of 10
OpenStudy (candy13106):
Yea
OpenStudy (isaidavila):
5√24 times 3√10
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OpenStudy (candy13106):
Yea
OpenStudy (isaidavila):
We can separate that like this
5*√24*3*√10
OpenStudy (candy13106):
K
OpenStudy (isaidavila):
(5*3)*(√(24*10)) we put 24 and 10 in the same root
OpenStudy (isaidavila):
15√240
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OpenStudy (candy13106):
K
OpenStudy (candy13106):
So is that it?
OpenStudy (isaidavila):
But 240=(2^4)*15
So
√(2^4)*15
√16*√15
4√15
OpenStudy (isaidavila):
15*4√15
60√15
OpenStudy (candy13106):
Thanks