4x^2-28x+49=0
I need to factor this, but with with quadratic formula. Can you show me the steps and the answer? Will medal.

Question

4x^2-28x+49=0
I need to factor this, but with with quadratic formula. Can you show me the steps and the answer? Will medal.

isaidavila · Answer

a=4
b=-28
c=49

kikuo · Answer

@isaidavila can you show how you got your answer?

mathstudent55 · Answer

Use the quadratic formula.
First, write the quadratic formula.
Then rewrite it substituting 4 for a, -28 for b, and 49 for c.
What do you get?

isaidavila · Answer

Just have to replace those values I gave you in the formula

mathmale · Answer

You are given    4x^2-28x+49=0
and need to pick out the coefficient of each of the 3 terms on the left.
That's where the {4, -28, 49} comes from.

mathmale · Answer

Please type out (or draw) the quadratic formula, so I can be certain that you know it.

kikuo · Answer

@mathstudent55 
ax^2+bx+c=0
4x^2-28x+49=0

kikuo · Answer

@isaidavila 
Is this correct?

mathmale · Answer

Yes.  Notice how the first coefficient is a = 4, the second b = -28 and the third c = 49.

tO FIND THE roots of this quadratic equation, we substitute these values of a, b and c in to the quadratic formula:$$x=roots=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

mathmale · Answer

Note that -b in this equation becomes -(-28) = + 28.