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OpenStudy (arindameducationusc):
i will try
OpenStudy (arindameducationusc):
45/54 for each bus stop
OpenStudy (arindameducationusc):
and so per hour
45/54*(1hr)
that should be the answer
OpenStudy (arindameducationusc):
i will ask @phi
he is online
OpenStudy (phi):
yes, 45/54 or 5/6 of an hour is how long it drives. that leaves 1/6 hr (10 mins) when it is stopped.
You can think of it a few ways.
One way is to say, if it drives for 1 hour, it will go 54 km (use rate * time = distance)
but it only went 45 km, so it did not drive for 1 hour:
54*t= 45
t= 45/54= 5/6
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OpenStudy (phi):
another way to think of it:
let t be a fraction of an hour when it is driving
and (1-t) the fraction it is not driving (going 0 kph)
then the distance it goes in 1 hour is
54*t + 0*(t-1) = 45
(same equation, but we are "averaging" the speeds 54 and 0 )
OpenStudy (mathmath333):
ok thnks
OpenStudy (phi):
btw, the answer is 1/6 hour not 5/6, because they are asking how long it is stopped per hour