graph..

x = 3 sin^3t
y = 3 cos^3t

Question

graph..

x = 3 sin^3t
y = 3 cos^3t

mathmale · Answer

Note that there is ambiguity in your post.  Do you mean "the cubes of cos t and sin t"?  or do you mean cos ^ (3t) and sin ^ (3t)?   Please clear this up to the best of your ability.

You could make a table of values and let t be your independent variable.  Let t=0, .  Calculate the coordinates (x,y) for each t value to form a single point.  Plot these points.

anonymous · Answer

it is the cubes of of cos t and sin t

$$3 \sin ^{3} t$$

anonymous · Answer

@mathmale

anonymous · Answer

@Nnesha

mathmale · Answer

OK.  Then$$x=3\sin^3t,y=3\cos^3t$$

mathmale · Answer

What are x and y when t=0?
What would x and y be were t=pi/6?

anonymous · Answer

hm.. how do i find that again?

anonymous · Answer

@mathmale

anonymous · Answer

@dan815

mathmale · Answer

$$x=3\sin^3t,y=3\cos^3t$$

Evaluate these formulas for x and y at t=0, t=pi/6, y=pi/3, and so on.

Example:  at t=0, x=3*(sin 0)^3= 3*(0)^3 = 0.