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Can someone show me how one would find if The sum of 1/3^n would converge? I don't know what test to use...
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I'm thinking comparison test, but I don't know how to show anything besides p-test
\[\sum_{n=1}^{\inf} 1/3^n\]
Here is what I am thinking:
ohhhh a geometric sequence! so you are saying the geometric series is 3^(-n)? I can use that to compare it to.
The first term would be 1/3, right? So, a = 1/3 The common ratio, r = also 1/3.
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=1/2, satisfying |r|<1, Thanks!
3^(-n) is the same as (1/3)^n So, I did 1/3 /(1 - (1/3) ) = 1/2 which is what you got.
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