What is the constant of variation for the quadratic variation? 6y=9x2 A.4/9 B.2/3 C.3/2 D.-2
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OpenStudy (foreveralone01):
I'll fan and medal is you get it right
OpenStudy (foreveralone01):
If*
OpenStudy (foreveralone01):
@AloneS okay thank you I'll see if it helps
alones (alones):
medal zepdrix xP
zepdrix (zepdrix):
Hey there :)
When we have a relationship like this: \(\large\rm y=kx^2\)
Then \(\rm k\) is our constant of proportionality.
So in this equation,\[\large\rm 6y=9x^2\]Dividing by 6 gives us,\[\large\rm y=\frac96x^2\]So we can clearly see that 9/6 is our constant \(\rm k\)!
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zepdrix (zepdrix):
You'll need to simplify this value to match it up to the correct option. :)
OpenStudy (foreveralone01):
@zepdrix okay thanks :)
OpenStudy (foreveralone01):
@zepdrix none of them matched the correct answer tho.....
zepdrix (zepdrix):
9/6 Reduce!! :O
Numerator and denominator are divisible by 3,
take a 3 out of each.