Question

can someone help me with the problem Im about to post below.

Answer 1

mhmm

Answer 2

\[81^{4x-3} =27^{3(5x-1)}\]

Answer 3

gimme one sec

Answer 4

ok

Answer 5

x=-3/29

Answer 6

how?

Answer 7

no idea I just put it into an online calculator, tbh

Answer 8

winter

Answer 9

Since the bases are the same, set the exponents equal to each other.

Answer 10

ok

Answer 11

Hey do you still need some help with that

Answer 12

yes please

Answer 13

okay

Answer 14

so tell me what can divide 27

Answer 15

9 and 3

Answer 16

okay good and i know you know that 3 and 9 can divide 81 right

Answer 17

yup

Answer 18

okay then since we both know this can we perform a crazy magic

Answer 19

yes

Answer 20

how many times can 3 divide 81

Answer 21

27

Answer 22

what is the \[\sqrt[4]{81}\]

Answer 23

3

Answer 24

how about
\[\sqrt[3]{27}\]

Answer 25

wouldn't it be 3 as well ?

Answer 26

because 3*3*3= 27

Answer 27

oh yes now you have just change your question to a simple on here is how it looks like now\[3^{4(4x-3)}=3^{3(3(5x-1))}\]

Answer 28

so since they're the same bases I would just set the equations

Answer 29

yes then you cancel out the 3 and work on the equation

Answer 30

would I start by distributing after I have cancelled out the 3

Answer 31

i mean this\[4(4x-3)=3(3(5x-1))\]

Answer 32

now can you find x

Answer 33

yes but how do I start ? Do I distribute

Answer 34

okay work on this first 3(5x-1)

Answer 35

that would equal 15x-3

Answer 36

okay now finish it up
4(4x-3)=3(15x-3)

Answer 37

I don't know what to do

Answer 38

okay 4(4x-3) solve that out first

Answer 39

16x-12?

Answer 40

okay do the same thing to 3(15x-3)

Answer 41

so it would be 16x-12=45x-9?

Answer 42

oh that is good can you finish it up now

Answer 43

what is x

Answer 44

-29/3

Answer 45

okay hold on
16x-45x=12-9
-29x=3

Answer 46

what is x

Answer 47

3/-29

Answer 48

oh ok now i see why

Answer 49

yes

Answer 50

:)

Answer 51

thank you so much :)

Answer 52

you are welcome