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Mathematics 14 Online
OpenStudy (lordhelix8th):

can anyone help me with this question?

OpenStudy (lordhelix8th):

Mr. Grayson owns a wood company that sells trees. Mr. Grayson gets a request from a customer to buy a palm tree of a specific height. Mr. Grayson’s tree nursery is very large and is organized by a coordinate plane map system. He finds a palm tree that he thinks might meet the customer’s specifications. The tree is located at coordinates (35, 28). He calls his assistant to come over to help him determine the height of the tree. He asks his assistant where she’s located. His assistant says she is located at (70, 15). Each unit on the coordinate grid represents 1 ft. How far is Mr. Grayson’s assistant from the tree? Round to the nearest tenth. Show your work.

OpenStudy (dogzcatz):

what is the question

OpenStudy (lordhelix8th):

no

OpenStudy (lordhelix8th):

that the image

OpenStudy (lordhelix8th):

OpenStudy (lordhelix8th):

@Serenity74 is you gona help orr?

OpenStudy (lordhelix8th):

@jabez177 @Hero

OpenStudy (lordhelix8th):

i kinda need help today, its due in 40 mins.

OpenStudy (lordhelix8th):

....

OpenStudy (lordhelix8th):

@pooja195

Mehek (mehek14):

Distance formula \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

OpenStudy (lordhelix8th):

ok

Mehek (mehek14):

plug in the values

OpenStudy (mrnood):

tghe trees are irrelevant this is sim[plt yhe distance between two points in the XY plane use the equation given above by @Mehek14

OpenStudy (lordhelix8th):

so (70^2-15^1)^2+(35^2-28^1)^2 ?

OpenStudy (lordhelix8th):

@MrNood

OpenStudy (lordhelix8th):

@MrNood ?

OpenStudy (lordhelix8th):

am i right @just_one_last_goodbye ?

OpenStudy (lordhelix8th):

@imqwerty

OpenStudy (lordhelix8th):

@myininaya

OpenStudy (lordhelix8th):

imqwerty am i right?

imqwerty (imqwerty):

no you made a lil mistake

OpenStudy (lordhelix8th):

hmm

imqwerty (imqwerty):

see if we got the coordinates of 2 points as-> \((x_1,~y_1)\) and \((x_2,~y_2)\) then the distance between then is given by this formula-> \(distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\) now your points are->(35, 28) and (70, 15) now see what is \(x_1,~x_2,~y_1,~y_1\) and then substitute appropriate values and solve

OpenStudy (lordhelix8th):

so add the points into the distance equasion?

imqwerty (imqwerty):

write the equation

OpenStudy (lordhelix8th):

s

imqwerty (imqwerty):

i mean like what will be the equation when you substitute the values of \(x_1,~y_1,x_2,y_2\)

OpenStudy (lordhelix8th):

i really dont know, i just started this type of math, sorry im dumb :(

imqwerty (imqwerty):

its alright dude its a bit confusing here are corresponding values |dw:1455660420357:dw| now try to put them in equation

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