The length of a rectangle is 6 meters more than its width. If the area of the rectangle is 135 square meters, find its dimensions.
wait so is it x+6 or x2+6x
I'm a little confused sorry
hold on
\(2L+2W=135\\L=6+W\\2(6+W)+2W=135\)
w x w + 6 = 135 w2 + 6w - 135 =0 Ie (w - 9)(w + 15) = 0 width = 9m (length = 15m)
now distribute \(2(6+W)\)
Now I'm really confused. I don't understand this at all
do you know distribution?
Not really. Could you explain please?
\(\Large{a(b+c)=a*b+a*c}\) Multiply what's on the outside with everything on the inside.
@trisha001 can you do it now?
so I solve a*b+a*c first? and multiply it with a(b+c) ?
no you multiply a(b+c) which gives you a*b + a*c do that with 2(6+W)
so now I multiply 2(6+w) a(b+c) or 2(6+w) and a*b+a*c
I'm sorry for being so confused
a(b+c) was just an example '-' 2(6+W) = 2*6 + 2*W
@Serenity74
alright sorry
when I did the problem I got 0=0 is that correct?
???
2(6+W) = 2*6 + 2*W
2*6 = ?
I can't figure it out. So thank you for taking your time to help but I'm having a lot of trouble so it's okay.
Oh oke. . . Well I have to go off. . . So I'll see if someone else can help :)
I finally got it now so thank you anyways but I figured it out ((: I really do appreciate it though.
yw :)
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