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Mathematics 12 Online
OpenStudy (anonymous):

Determine the wavelength of radiation with a frequency of 1.50x10^13s^-1. Does this radiation have a longer or shorter wavelength than red light? I don't want just the answer i would love an explanation please :)

OpenStudy (anonymous):

@pooja195

OpenStudy (astrophysics):

Recall the equation \[v = \frac{ d }{ t }\] similarly we have a relationship for wavelength and frequency which follows \[c = \lambda f\] where c is the speed of light, lambda is the wavelength and f is frequency.

OpenStudy (astrophysics):

|dw:1455678577179:dw|

OpenStudy (anonymous):

So how would I plug in the information to the equation? my teacher did not explain anything and just gave us work and a quiz tomorrow

OpenStudy (kingbowzer):

c is a constant (speed of light), and it appears you are given frequency. @Astrophysics provided an equation that relates these two quantities (they are proportional with proportionality lambda). @Astrophysics also provided motivation for unit analysis.

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