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OpenStudy (anonymous):
how do i find the equation of the tangent line to the curve at y=secx-2cosx at P=(pi/3, 1)
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OpenStudy (sweetburger):
You need to first take the derivative of the function. Now that you have the derivative plug in pi/3 for each x value. Your resulting value is the slope of the tangent line at (pi/3,1. Using slope intercept create an equation for the line.
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