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Mathematics 14 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

@Michele_Laino

OpenStudy (welshfella):

the domain will be all values of x except the value which makes the denominator of the fraction ( x +1) = 0.

OpenStudy (welshfella):

what values is that?

OpenStudy (anonymous):

0

OpenStudy (welshfella):

no - what value of x makes x+ 1 = 0?

OpenStudy (anonymous):

-1

OpenStudy (welshfella):

right

OpenStudy (anonymous):

ok

OpenStudy (welshfella):

\[{x \in R : x =\neq -1}\]

OpenStudy (anonymous):

thats the answer ?

OpenStudy (welshfella):

thats the domain

OpenStudy (anonymous):

okay how do we find the range

OpenStudy (welshfella):

well the value of the function cannot be - 8 so its all real values of y except -8

OpenStudy (anonymous):

so 8?

OpenStudy (welshfella):

No ALL real numbers but not -8

OpenStudy (anonymous):

thats the range all real numbers?

OpenStudy (welshfella):

its written similar to the domain but put y instead of x and not equal -8 instead of not eqqqualto -1

OpenStudy (anonymous):

-8 doesnt equal -1

OpenStudy (welshfella):

you do not follow me look at my 5th post

OpenStudy (anonymous):

so the domain is also the range?

OpenStudy (welshfella):

no write y instead of x and -8 instead of -1 and youy have the range

OpenStudy (anonymous):

y= -1

OpenStudy (welshfella):

\[y \in R: y \neq-8\]

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

how do we do asymptotes

OpenStudy (welshfella):

what value of x gives no value for y?

OpenStudy (welshfella):

we determined this already

OpenStudy (anonymous):

-1 and -8

OpenStudy (welshfella):

no just x = 1 thats the asymptote

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

the x intercept is -8 and y is -1

OpenStudy (welshfella):

to find the y intercept just replace the x in the function by 0 and work out the value of y to find the x intercepts just replace the y by 0 and solve for x that is solve 10 / (x +1) - 8 = 0

OpenStudy (welshfella):

so to find y-intercept you need to calculate 10 ----- - 8 0 + 1

OpenStudy (anonymous):

x = 1/4

OpenStudy (welshfella):

thats correct for x-intercept

OpenStudy (anonymous):

ok and Y?

OpenStudy (welshfella):

now find the y -intercept

OpenStudy (welshfella):

- i showed you in my post

OpenStudy (welshfella):

x = -1 is the asymptote - i said x = 1 which was wrong

OpenStudy (welshfella):

y intercept is 10 / (0+ 1) - 8

OpenStudy (welshfella):

gotta go right now

OpenStudy (anonymous):

how do you graph it?? ?

OpenStudy (anonymous):

@Michele_Laino i need help im graphing it

OpenStudy (michele_laino):

we can use the graphic calculator

OpenStudy (anonymous):

what do i put in

OpenStudy (anonymous):

numbers 1 and 2?

OpenStudy (michele_laino):

please, enter this information: \[y = \left[ {10/\left( {x + 1} \right)} \right] - 8\] as I wrote

OpenStudy (anonymous):

okay i did

OpenStudy (anonymous):

is that it

OpenStudy (michele_laino):

please post the graph you got

OpenStudy (anonymous):

OpenStudy (anonymous):

thats right?

OpenStudy (michele_laino):

please wait....

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

I got this:

OpenStudy (michele_laino):

please note the formula which I wrote is different from the one you wrote

OpenStudy (anonymous):

i guess ok is that it

OpenStudy (michele_laino):

similarly for second function, please try to enter this formula: \[y = \left[ {2/\left( {x + 6} \right)} \right] - 1\] in the same way as I wrote

OpenStudy (anonymous):

OpenStudy (michele_laino):

that's right!

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