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Mathematics 20 Online
OpenStudy (anonymous):

where does the graph of this function cross the x-axis?

OpenStudy (anonymous):

OpenStudy (anonymous):

set the numerator (top) equal to zero and solve for \(x\) a fraction is only zero if the numerator is zero

OpenStudy (okdutchman7):

It crosses the y axis at -2

OpenStudy (hybrik):

set y to 0

OpenStudy (hybrik):

and solve for x

OpenStudy (okdutchman7):

and crosses the x axis at-24/11 Put that in a calculator and check

OpenStudy (hybrik):

@okdutchman7 u have to explain :P

OpenStudy (anonymous):

Would the answer be -12,2

OpenStudy (anonymous):

this is what you have to solve :\[x^2+14x+24=0\]

OpenStudy (hybrik):

@chachi123 x^2+14x+24=0, solve for x

OpenStudy (okdutchman7):

Solve by using the quadratic formula.

OpenStudy (anonymous):

you are close, but not \(2\) it would be \(2\) after you factor this as \[(x+2)(x+12)=0\]

OpenStudy (hybrik):

and u get -2,-12

OpenStudy (anonymous):

oops i meant "not 12, -12"

OpenStudy (hybrik):

gg explained b4 me :P

OpenStudy (anonymous):

I had got -12,-2

OpenStudy (anonymous):

Thank you!

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