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where does the graph of this function cross the x-axis?
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set the numerator (top) equal to zero and solve for \(x\) a fraction is only zero if the numerator is zero
It crosses the y axis at -2
set y to 0
and solve for x
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and crosses the x axis at-24/11 Put that in a calculator and check
@okdutchman7 u have to explain :P
Would the answer be -12,2
this is what you have to solve :\[x^2+14x+24=0\]
@chachi123 x^2+14x+24=0, solve for x
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Solve by using the quadratic formula.
you are close, but not \(2\) it would be \(2\) after you factor this as \[(x+2)(x+12)=0\]
and u get -2,-12
oops i meant "not 12, -12"
gg explained b4 me :P
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I had got -12,-2
Thank you!
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