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Mathematics 7 Online
OpenStudy (barrera1):

What is the volume of the trapezoidal right prism? A. 51 m3 B. 624 m3 C. 960 m3 D. 1248 m3

OpenStudy (barrera1):

OpenStudy (barrera1):

Could you help me with one more @xMissAlyCatx ?

OpenStudy (xmissalycatx):

I actually have to go. Try to tag a qualified helper or a moderator.. Have a lovely day! <3

OpenStudy (barrera1):

ok thanks for the help on the last one @xMissAlyCatx :)

OpenStudy (barrera1):

@Michele_Laino

OpenStudy (michele_laino):

the volume \(V\), is: \[\Large V = {\text{base area }} \times {\text{ height}}\]

OpenStudy (michele_laino):

where the height is \(4\) meters so, we have to compute the base area, which is the area of an isosceles trapezoid

OpenStudy (barrera1):

So is it 30 * 8?

OpenStudy (barrera1):

@mathmale I posted it already

OpenStudy (michele_laino):

base area= area of the trapezoid, and area of the trapezoid = \(A = \frac{{\left( {30 + 9} \right) \times 8}}{2} = ...?\)

OpenStudy (michele_laino):

\[\huge A = \frac{{\left( {30 + 9} \right) \times 8}}{2} = ...?\]

OpenStudy (barrera1):

156?

OpenStudy (michele_laino):

correct! So, the requested volume is: \[\Large V = {\text{base area }} \times {\text{ height}} = 156 \times 4 = ...?\]

OpenStudy (mathmale):

What's your '156' meant to represent? Much of this work would make more sense to you if you'd make a point of using units of measurement. 156 what? (units of measurement?)

OpenStudy (barrera1):

624

OpenStudy (michele_laino):

that's right!! :) more precisely: we can write this: \[\Large A = \frac{{\left( {30 + 9} \right) \times 8}}{2} = 156\;{m^2}\] \[\Large V = {\text{base area }} \times {\text{ height}} = 156 \times 4 = 624\;{m^3}\]

OpenStudy (mathmale):

Again, please use units of measurement. Do you mean 624 years? 624 cows? Seriously, it's important to indicate what you are measuring.

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