Question

Evaluate.

Answer 1

https://static.k12.com/bank_packages/files/media/mathml_1d8bd572647f29e88f6c517884f0e5a94195b054_1.gif

Answer 2

WILL MEDAL

Answer 3

\[\large\rm \frac{-8\left[\color{orangered}{(12-6)}+3\right]+4}{9-2(2+3)}\]We prioritize brackets or parenthesis highest,
so let's start with these brackets within brackets.

Answer 4

6

Answer 5

\[\large\rm \frac{-8\left[\color{orangered}{6}+3\right]+4}{9-2(2+3)}\]k what next?
We should probably stay in this room, this set of brackets, ya?

Answer 6

\[\large\rm \frac{-8\color{orangered}{\left[6+3\right]}+4}{9-2(2+3)}\]

Answer 7

9

Answer 8

\[\large\rm \frac{-8\color{orangered}{(9)}+4}{9-2(2+3)}\]k good.
Finish the numerator by multiplying before adding.

Then we move onto the denominator.

Answer 9

\[\frac{ -8(9)+4 }{ 9-2(5) }\]

Answer 10

@zepdrix

Answer 11

\[\large\rm \frac{ \color{royalblue}{-8(9)}+4 }{ 9-\color{royalblue}{2(5)} }\]k good.
Do your multiplication steps before addition.

Answer 12

\[\frac{ -68 }{ -1 }\]

Answer 13

Correct?

Answer 14

@zepdrix

Answer 15

yay good job \c:/

Answer 16

It can simplify a tiny bit further, ya?

Answer 17

negative divided by negative is positive.
and dividing by 1 is trivial, we can suppress it.\[\large\rm \frac{-68}{-1}=\frac{68}{1}=68\]

Answer 18

ok

Answer 19

is that the answer?

Answer 20

yes