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Mathematics 7 Online
OpenStudy (imsleeziboii):

HELP!!

OpenStudy (imsleeziboii):

How would you write 0.3y + 1.2 = –0.4x in standard form?

OpenStudy (anonymous):

Standard form is y=mx+b So all we have to do is put the y on one side of the equal sign, alone. 0.3y+1.2=-0.4x *subtract 1.2* .3y=-0.4x-1.2 *divide .3y by .3, to get the y alone* y= -(.4x/.3) -(1.2/.3) *simplify* y= -.4x/.3 - 4 ((because -1.2/.3 = -4)

OpenStudy (imsleeziboii):

how did you write that so fast..

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