Ask your own question, for FREE!
Physics 6 Online
OpenStudy (anonymous):

Resistors HELP ME!!!

OpenStudy (anonymous):

If two resistors (R1 and R2), where R1<R2, are connected in parallel. The slope of V versus I should be Less than R1 Less than R2 Greater than R1 but less than R2 Greater than R2 Explain your choice

OpenStudy (anonymous):

THIS IS QUESTION IS SIMILAR (DIFFERENT RELATION)

OpenStudy (z4k4r1y4):

The question you have here is exactly the same as the similar question you’ve posted. The only difference is that here R2 > R1 instead of R1 > R2.

OpenStudy (anonymous):

YES BUT I THINK THE ANSWER IS DIFFERENT

OpenStudy (michele_laino):

hint: we can write this equation: \[I = \frac{V}{{{R_{EQ}}}} = V\left( {\frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}} \right)\] so we get: \[V = mI\] where the slope \(m\), is such that: \[\frac{1}{m} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\] now, if \(R_2>R_1\), then we can write: \[\frac{1}{m} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} \geqslant \frac{1}{{{R_1}}}\]

OpenStudy (anonymous):

so you are saying the slope of R2 is greater than R1 , but the choices confuses me

OpenStudy (anonymous):

is it less than R1!! where \[m=R1+R2 \le R1\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103: How to pop out like a Jacc In the box
7 hours ago 0 Replies 0 Medals
Breathless: Spooky witch but cute
14 hours ago 3 Replies 0 Medals
Arriyanalol: help
14 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
16 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
16 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!