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Algebra
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Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).
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y = 0 for the x-intercept(s)
x = 0 for the y-intercept(s)
where is the parabola?
Looks like the logical approach is to find the equation of the parabola first. You are told, "Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6)." The standard equation of a parabola relevant to this case is y-k=a(x-h)^2, where (h,k) represents the vertex and (x,y) is a point on the parabola. Insert the given info about vertex and point, solving the resulting equation for the coefficient, a. Write out the equation for this particular parabola. Now let y=0 and solve for x. That is / are your horizontal intercept(s).
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