A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic energy?

E = mc2
PE = mgh
ME = KE + PE
KE = ½mv2

Question

A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic energy?
 	
	E = mc2
	PE = mgh
	ME = KE + PE
	KE = ½mv2

andrewkaiser333 · Answer

@hartnn

imqwerty · Answer

are you familiar with kinetic energy and calculations based on it?
this is basic formula for kinetic energy tried searching it in your book or somewhere? :)

andrewkaiser333 · Answer

did not get my books yet and just started this today.

jim_thompson5910 · Answer

The formula for kinetic energy is $$\Large KE = \frac{1}{2}mv^2$$

KE = kinetic energy
m = mass
v = velocity

this should be found in your book (when you get it) either in the first chapter or in the appendix

andrewkaiser333 · Answer

thanks