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The midsgement of a trapezoid is give by \[EF = \frac{ AD + BC }{ 2 }\] From the problem you are given that AD = x + 1 BC = 10 and EF = 3x-2
yup
Just plug those vales in. Then you will have an equation in which you can solve for x.
oh okay thx
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19. The sum of the lengths of BC and AD is twice the length of EF. 10 + (x + 1) = 2 (3 x - 2)
@robtobey can i do that to 20 also?
ef=13?
21. is the same set up or idea as 19.
okay but can u check if ef=13?
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?
Neither of them is 13.
19.) 10 + (x + 1) = 2 (3 x - 2) 21.) 2 ( x+3) = x-2 + 2x For both equations solve for x. I'll do 21.) for you. 2x + 6 = x -2 + 2x 2x + 6 = 3x - 2 8 = x Number 21.) x = 8 Do the same for 19.)
okay thx
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