Question

Differentiation

Answer 1

What have you tried so far '?

Answer 2

Well, quite frankly I don't even know...

Answer 3

so you have \[-1=\frac{1}{a+b}\]

and \[2=\frac{-b}{(a+b)^2}\]

square the first equation

\[(-1)^2=\left(\frac{1}{a+b}\right)^2\]

\[1=\frac{1}{(a+b)^2}\]

replace into the 2nd equation

\[2=\frac{-b}{(a+b)^2}=-b\]

thus \[b=-2\]


replace b=-2 into the first equation
\[-1=\frac{1}{a-2}\]

and solve for a...you will get 1

Answer 4

I just realized my mistake, I was bringing -b down along with the expression to the denominator. Darn it! Thanks