I used the lateral area formula: p*h where p is the perimeter of the triangular base and h is the height
(2 + 5 + 5.39) * 26 = ? for the lateral area @shaleiah
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563blackghost (563blackghost):
\(\huge{LA=(a+b+c)h}\)
A=2
B=5
C=5.39
H=26
OpenStudy (shaleiah):
147.14
Directrix (directrix):
To this answer: (2 + 5 + 5.39) * 26 = ? for the lateral area
add 2 times the area of the right triangular base to get the total area of the prism.
@shaleiah
Directrix (directrix):
147 is not the answer to this: (2 + 5 + 5.39) * 26 =
@shaleiah Try again.
OpenStudy (shaleiah):
322.14
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Directrix (directrix):
Correct. 322 when rounded.
Directrix (directrix):
The area of the right triangle base is 1/2 * 2*5 = ? @shaleiah
Directrix (directrix):
Double what you get for this: 1/2 * 2*5 = ?
because there are 2 bases.
Directrix (directrix):
Add 322 to what you get for the areas of the two bases.
Directrix (directrix):
Nope.
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Directrix (directrix):
2 * 1/2 * 2*5 = 10 for the two bases.
What is 10 + 322 ? @shaleiah