@directrix
area of three rectangles=26*5+26*2+26*5.39=? area of two triangles=\[=2*\frac{ 1 }{ 2 }*5*2=?\] add the two areas.
Sorry, 10.
\(\huge\color{green}{SA = wh + lw + lh + ls}\) W=5 L=26 H=2 S=5.39
I used the lateral area formula: p*h where p is the perimeter of the triangular base and h is the height (2 + 5 + 5.39) * 26 = ? for the lateral area @shaleiah
\(\huge{LA=(a+b+c)h}\) A=2 B=5 C=5.39 H=26
147.14
To this answer: (2 + 5 + 5.39) * 26 = ? for the lateral area add 2 times the area of the right triangular base to get the total area of the prism. @shaleiah
147 is not the answer to this: (2 + 5 + 5.39) * 26 = @shaleiah Try again.
322.14
Correct. 322 when rounded.
The area of the right triangle base is 1/2 * 2*5 = ? @shaleiah
Double what you get for this: 1/2 * 2*5 = ? because there are 2 bases.
Add 322 to what you get for the areas of the two bases.
Nope.
2 * 1/2 * 2*5 = 10 for the two bases. What is 10 + 322 ? @shaleiah
332
And, the correct option is ?
d
\(\Huge\cal\rlap{\color{red}{Correct:)}}{\color{blue}{\;Correct:)}}\)
Good work, everyone!
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