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Mathematics 21 Online
OpenStudy (anonymous):

A circle is cut from a square piece of cloth, as shown: A square, one side labeled as 38 inches, has a circle inside it. The circle touches all the sides of the square. The portion of the square outside the circle is shaded. How many square inches of cloth are cut from the square? (π = 3.14) 1,052.00 in^2 1,133.54 in^2 1,444.00 in^2 1,584.34 in^2

OpenStudy (anonymous):

A 👑👑

OpenStudy (anonymous):

thxs :3

OpenStudy (anonymous):

ur welcome

OpenStudy (anonymous):

can u help me with one more problem?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

A running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 62 m and length of one straight edge 100 m What is the perimeter of the inside of the track? (π = 3.14) 162.00 m 324.00 m 394.68 m 589.36 m

OpenStudy (anonymous):

easy I did this one not to long ago 394.68 M

OpenStudy (anonymous):

ur a life savor thank u!

OpenStudy (anonymous):

ur welcome wait let me fan u

OpenStudy (anonymous):

wait can u help me with one more question :3 derp

OpenStudy (anonymous):

Ned wrote the following statement: "You can only draw one unique isosceles triangle that contains an angle of 80°." Which statement is true? Ned is correct, because only one unique triangle can be drawn with the given information. Ned is incorrect, because the triangle described cannot be drawn with the given information. Ned is incorrect, because more than one triangle can be drawn with the given information. None of the above.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

this one is confusing

OpenStudy (anonymous):

I pretty sure it is none of the above

OpenStudy (anonymous):

okay thx again!

OpenStudy (anonymous):

do u need help on another one

OpenStudy (anonymous):

yes let me open a new thread so i can medal u more :D

OpenStudy (anonymous):

ok cool

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