Simplify 7 log3 k + 6 log3 m − 9 log3 n

4 log3 km over n

4 log3 (k + m − n)
log3 k to the seventh power m to the sixth power over n to the ninth power

log3 42 km over 9 n

Question

Simplify 7 log3 k + 6 log3 m − 9 log3 n

         4 log3 km over n 

	4 log3 (k + m − n)
	log3 k to the seventh power m to the sixth power over n to the ninth power 

	log3 42 km over 9 n

babeberry · Answer

@mathstudent55 welp?

babeberry · Answer

$$\log_{3}(k)^{7}+\log_{3}(m)^{6}-\log_{3}(n)^{9}$$

babeberry · Answer

$$\log_{n} x+\log_{a}y=\log_{a}(x*y)$$
$$\log_{3}(k^{7} *m^{6})-\log_{3} (n)^9$$

babeberry · Answer

@jdoe0001 Can u help me with the rest? plz

jdoe0001 · Answer

one sec.. but you're doing fine

zepdrix · Answer

Try to get in the habit of putting the exponents inside of the brackets :)$$\log_{3}(k^7)+\log_{3}(m^6)-\log_{3}(n^{9})$$Otherwise it looks like the power is being applied to the log (which is something different.

jdoe0001 · Answer

hmm I ended up with a y lol, darn typo
anyhow $\bf 7log_3k+6log_3m-9log_3n\implies log_3(k^7)+log_3(m^6)-log_3(n^9)
\ \quad \
log_3(k^7m^6)-log_3(n^9)\implies log\left(  \cfrac{k^7m^6}{n^9}\right)$

babeberry · Answer

So the next step was the answer?

jdoe0001 · Answer

yeap

babeberry · Answer

Oh okey. I knew the answer I just needed to know how to get there. Thx u both :)

jdoe0001 · Answer

yw