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Mathematics 7 Online
OpenStudy (ray1998):

Please help! Will give both fan and medal. Find the inverse of the relation shown below. Graph the given relation and its inverse. (Chart will be posted below) Thank you!!

OpenStudy (ray1998):

OpenStudy (ray1998):

I know that if you graph the original relation, the slope is at 0 and the y-intercept is at 2. I'm just not sure how to find the inverse.

OpenStudy (ray1998):

Can any of you help? @Theloshua @Aygunka @barrycarter

OpenStudy (agent0smith):

Finding the inverse from a table of values is super easy. Swap the x's with the y's. That's your inverse.

OpenStudy (ray1998):

Alrighty, that's it?

OpenStudy (ray1998):

Which means I would graph it the same way.. Okay! Got it :) thank you! @agent0smith

OpenStudy (agent0smith):

Since the first point is (0, 1), the inverse would be (1, 0). Do the same with the rest.

OpenStudy (ray1998):

Okay :) thank you for replying.

OpenStudy (jdoe0001):

\(\begin{array}{rrllll} x&y \\\hline\\ {\color{brown}{ 1}}&0\\ {\color{brown}{ 2}}&-1\\ {\color{brown}{ 4}}&0\\ {\color{brown}{ 6}}&4\\ {\color{brown}{ 8}}&8\\ {\color{brown}{ 10}}&9\\ {\color{brown}{ 11}}&8 \end{array}\qquad inverse\implies \begin{array}{rrllll} x&y \\\hline\\ 0&{\color{brown}{ 1}}\\ -1&{\color{brown}{ 2}}\\ 0&{\color{brown}{ 4}}\\ 4&{\color{brown}{ 6}}\\ 8&{\color{brown}{ 8}}\\ 9&{\color{brown}{ 10}}\\ 8&{\color{brown}{ 11}} \end{array}\)

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