Proving Trig Equations:
Can you tell I'm having a lot of trouble with this section? Question coming in a sec!
\[2 \arctan \frac{ 1 }{ 2 } = arcos \frac{ 3 }{ 5 }\]
*Prove the above! So far I tried: \[2 \tan x = \cos y \] So: \[1 = 3/5 ?\] Obviously I'm not going about this the right why, but I'm kind of at a loss here.
Alternatively I tried: \[2 \arctan 1/2 - \arccos 3/5 = 0 = 2x-y = 0 = \cos (2x-y) = \pi/2\]
\[= \cos 2x \cos y + \sin 2x \sin y = \pi/2\]
If tan x = 1/2 and cos y = 3/5 sin x = 1/5 , cos x = 2/5 sin y = 4/5 , tan y = 4/3 etc etc, until I could replace all the values in the above equations with the relevant trig values. But I came up with 1/5 , which seems...unrelated to pi/2
Help would be greatly appreciated, I'm really battling with this. ;n;
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