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OpenStudy (math_man21):
hit me
OpenStudy (anonymous):
Domain of f
3x(power of 2) +1
(I hate my tablet :/)
OpenStudy (math_man21):
idk jk
hartnn (hartnn):
you mean you want the domain of
\(f(x) = 3x^2 + 1\)
??
well, what values does x cannot take?
OpenStudy (anonymous):
Yep
Wdym?
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hartnn (hartnn):
ok,
if we have a \(\sqrt..\), then the function inside that square root must be positive.
the values of x that make the \(\sqrt. \) negative are not in the domain.
similarly,
the denominator of a function cannot be = 0.
the values of x for which the denominator = 0 are not in the domain.
so for 3x^2+ 1
what are the values of x which are not in the domain of x?
OpenStudy (anonymous):
Wait, to find a domain, you would need to havea graph right?
hartnn (hartnn):
you can, thats one way.
what we are doing is trying to find it algebraiclally.
OpenStudy (anonymous):
Well then i have no clue cause i only learned by graph.
hartnn (hartnn):
so if you plot 3x^2 +1,
what do you observe ?
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hartnn (hartnn):
is there any value that x cannot take?
OpenStudy (anonymous):
Um, give me a min
OpenStudy (anonymous):
It can take any value...
hartnn (hartnn):
right!
so the domain is all real numbers :)
OpenStudy (anonymous):
Oh ok. Thanks! :D
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