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Express the sum using sigma notation: 1/2+2/5+3/10+4/17+5/26
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top is going up be 1 each time the bottom is a quadratic because the second differences are constant that is 2,5,10,17,26 first differences 3,5,7,9 second difference: 2,2,2
find a,b,c given \[f(n)=an^2+bn+c \text{ and } \\ f(1)=2 \\ f(2)=5 \\ f(3)=10 \\ ,...\]
using just that you will have a system of equations with 3 equations and 3 variables
you can solve that to find a,b, and c
however if you want to try to short cut things you can try to guess the quadratic pattern in the denominator
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i got the summation from k = 1 to 5 k+1/(k^2)
here is a hint for the denominator: 2=1^2+1, 5=2^2+1,10=3^2+1,..... also it looks your numerator needs a little fixing
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