Question

In a box are a carton of dairy milk and Boonville chocolates. Two items
are chosen at random from the box, without replacement. The probability of
selecting dairy milk and then a Boonville chocolate is 0.47. The probability of
selecting dairy milk on the first draw is 0.71. What is probability selecting a
Boonville chocolate on the second draw. Given that the first chocolate drawn
was dairy milk?

Answer 1

please help

Answer 2

Probability of choosing items in order is described as \[(probability of first item)\times (probability of second item)\]
And that equals overall probability
So I would solve\[.71x=.47\]
Where x is the probability of drawing a chocolate

Answer 3

the answer is 0.66197183098

Answer 4

Yep that's correct