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Mathematics 20 Online
OpenStudy (anonymous):

IF A, B and C are sets. Then A/B is a subset of C if and only if A/C is a subset of B. I need to create a proof for this and I am lost on how to go about it,

OpenStudy (anonymous):

what does A/B mean?

OpenStudy (anonymous):

In SET A less SET B

OpenStudy (anonymous):

i wonder if a picture would help

OpenStudy (anonymous):

I tried a picture...I have done by assigning values to each set and made it work

OpenStudy (anonymous):

my picture makes it seem like it is not true maybe we can come up with an easy counter example

OpenStudy (anonymous):

Set A {1,2,3,4} SET B = {3} Thus Set A/B is {1,2,4} Now make that SET C {1,2,4) So Set A= {1,2,3,4} Set C = {1,2,4} Then A/C = {3} which is a subset of B

OpenStudy (anonymous):

maybe we can try this Assume \(A\cap B^c\subset C\) and pick an \(x\in A\cap C^c\) and show that \(x\) must be in \(B\) if not , then \(x\in B^c\) and so in \(A\cap B^c\) which you know by assumption is contained in \(C\) contradicting it being in \(A\cap C^c\)

OpenStudy (anonymous):

no didn't i just wrote \(A\cap B^c\) instead of A/B

OpenStudy (anonymous):

I have x is an element of A and x is not and element of B is a Subset of C.

OpenStudy (anonymous):

right that is what i wrote with \(A\cap B^c\subset C\)

OpenStudy (anonymous):

is it clear how to structure this proof? you have to assume that \(A\cap B^c\subset C\) then pick an \(x\in A\cap C^c\) and show that it is in \(B\) that will prove that \(A\cap C^c\subset B\)

OpenStudy (zarkon):

Does anyone actually use A/B for set minus (I don't have any books that do this...and I have a lot of books) the usual notation is A\B or A-B

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