Find a particular solution of y"+3y'-2y=e^(-2x)[(4+20x)cos3x+(26-32x)sin3x].
\[y _{p}=e ^{-2x}(A+Bx)(\cos3x+\sin3x)\]
Is my initial guess right above?
@myininaya @Luigi0210
what the scooby that right hand side is monstrous
i think that looks like a fine guess
Because the answer is \[y _{p}=e ^{-2x}(1-2x)(\cos3x-\sin3x)\]
If the guess looks fine, then I'll try it.
you could throw in some more constant values \[y_p=e^{-2x}(Ax+B)( C \cos(3x)+D \sin(3x))\]
Okay, cool. While this may take time, I'll do the problem and tell you what I got.
if you try the first one and it fails see if that one works my guess is that last one work due to your - sign between the cos(3x) and the sin(3x)
I tried the second one which you suggested and it worked perfectly! Thank you so much for the help! God, that problem took a very long time to solve. But I'm happy. :)
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