Question

The system of linear equations
x+(sina)y+(cosa)z=0
x+(cosa)y+(sina)z=0
x-(sina)y-(cosa)z=0
has a non trivial solution for only one value of a lying in interval (0,π/2) .
Is statement true or false??

Answer 1

I m getting it true...

Answer 2

for non trivial solution,DETERMINANT SHOULD BE ZERO

Answer 3

Correct ...!

Answer 4

And if u solve the determinant then there will turn out to be one value of a for which determinant can be zero

Answer 5

Which is π/4

Answer 6

wait, lemme solve your first doubt

Answer 7

you are getting pi/4

Answer 8

so it is true statement

Answer 9

Nope ans is wrong

Answer 10

i didn't solve it yet

Answer 11

So , will u do it ?

Answer 12

wait, i'm solving now

Answer 13

is answer false ?

Answer 14

Obviously

Answer 15

Did u get it?

Answer 16

YE

Answer 17

Tell !

Answer 18

is bracket OPENED or CLOSED ?

Answer 19

Open

Answer 20

it is true for all values lies between 0 and pi/2

Answer 21

How is it possible ?
I got jst one value of a for which determinant is 0

Answer 22

try for a=30 degrees and a=60 degrees and tell me what you get ?

Answer 23

Did u do it in proper determinant way?

Answer 24

yeah !

Answer 25

okay,
show your work first

Answer 26

I got just one value from that condition... Cos 2a was remaining finally which would be 0 only for a =π/4

Answer 27

nothing is remaining

Answer 28

you done a calculation mistake