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@marcelie
okay so y^2-y^1/x^2-x^1
\[\frac{ 0-6 }{ -3-3 }\]
Right?
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so -6/-6
@marcelie
Use two point-point form of a linear equation: (y - y1) / ( x - x1) = (y1 - y2) / (x1 - x2)
(y - (-6)) / (x - 3) = (-6 - 0) / 3 - (-3))
\[\frac{ (y+6 }{ (x-3) }= \frac{ -6 }{ 6 }\] \[\frac{ (y+6) }{ (x-3) }= -1\]
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\[y+6=-1(x-3)\] \[y+6=-x+3\] Can u now find ur solution?
did you get it?
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