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OpenStudy (anonymous):

The registrar of a large university knows that 30% of the students come to college with credit for an advance placement (AP) course. The registrar is going to conduct interviews with students regarding their experiences at the university. Depending on which students are chosen, the proportion of students in the sample that have AP credit may vary. In a sample of 200 students, what is the probability that over 32% of the sample has AP credit?

OpenStudy (anonymous):

can you help explain this one?

OpenStudy (raffle_snaffle):

what is the question?

OpenStudy (anonymous):

sorry i posted the wrong thing

OpenStudy (raffle_snaffle):

so we need to find the sample proportion

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

first i would have to find the standard deviation though right?

OpenStudy (raffle_snaffle):

I believe so.

OpenStudy (anonymous):

so that would .00105

OpenStudy (kropot72):

The standard deviation is given by \[\large \sqrt{\frac {p(1-p)}{n}}\] Can you see what step you missed in your calcuolation?

OpenStudy (anonymous):

i forgot to take the square root

OpenStudy (anonymous):

so it would be .0324

OpenStudy (kropot72):

Correct!

OpenStudy (anonymous):

what would my next step be?

OpenStudy (anonymous):

@kropot72

OpenStudy (kropot72):

Now you need to find the z-score for 0.32.

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