Radicals Help
What do you need help with?
A) (√96/√6)-(√54/√6) √(96/6)-√(54/6) √16-√9= 4-3=1
@isaidavila dont we factor ou 96 then divide by 6 from there?
Is another way to do it
But do you understan D what I did?
Excellent, check out how I did the problem. we want to simplify the radicals as much as possible by finding a number that we can take the square root of and get an integer i.e. whole number. \[\frac{ \sqrt{96}-\sqrt{54} }{ \sqrt{6} } \] we must simplify this right? check this out \[\frac{ \sqrt{16}*\sqrt{6}-\sqrt{9}*\sqrt{6} }{ \sqrt{6} }\] \[\frac{ 4\sqrt{6}-3\sqrt{6} }{ \sqrt{6} } = \frac{ \sqrt{6}(4-3) }{ \sqrt{6} } = 1\]
if you're looking for another way to do it @SuperFly123
Thanks for that prob, now 22 im stuck at
@jhonyy9
so for what you wan help from these ?
from 22 and down
ok do you know how multiplie radicals ?
yes
there are squarroot multiplied squarroot - so how will be ? for example sqrt(a) *sqrt(b) = ?
You multiply the radicands then simpify
for the first answer it should be 4 radical 2 minus 3 not 1
do you think it about your exercise 22 - first exercise ?
for exercise 21 shouldn't the answer be 4 radical 2 minus 3
you have said me exercise 22 - no ?
i did but im asking you for 21 also
sqrt96 - sqrt54 --------------- = ---------------- sqrt6 how you solve it ?
Sorry the answer to 21 is correct i messed up , okay anyway exercise 22
sqrt96 = sqrt(6*16) = 4sqrt6 sqrt54 = sqrt(9*6) = 3sqrt6 4sqrt6 -3sqrt6 sqrt6*(4-3) -------------- = ----------- = (4-3) = 1 sqrt6 sqrt6 have you got it same ?
Sorry the answer to 21 is correct i messed up , okay anyway exercise 22
yes
are you here please ?
I have all the answers thank you for your time
ok was my pleasure good luck
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