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Mathematics 20 Online
OpenStudy (anonymous):

The quadratic functions f(x) and g(x) are described as follows: f(x) = −4x2 + 5 x g(x) 0 0 1 1 2 5 3 1 4 0 Which of the following statements best compares the maximum value of the 2 functions? It is the same for both functions. f(x) has a greater maximum value than g(x). g(x) has a greater maximum value than f(x). The maximum values cannot be determined.

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

To find the max is to find the vertex. Do you know how to do that?

OpenStudy (anonymous):

yup -b/2(a)

OpenStudy (anonymous):

Ok, well in our first equation you know that b is zero, yes?

OpenStudy (triciaal):

minor correction the vertex could be a minimum the maximum is the highest y-value of the function

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

I know this @triciaal I am working my way to that

OpenStudy (anonymous):

\[ f(x)=−4x^2 + 5 = −4(x-0)^2 + 5 \]It is already in vertex form.

OpenStudy (anonymous):

@wio I know that it is in vertex form, but that is not the vertex. In order to find the maximum or minimum they have to find the vertex

OpenStudy (triciaal):

if you know that then you should write it correctly. What if I did not know better?

OpenStudy (anonymous):

(0,5) is the vertex right?

OpenStudy (anonymous):

im just not sure what to do with the table

OpenStudy (anonymous):

The table is simple. When given a table the vertex is the one in the middle. So, (2,5) Now you should be able to answer

OpenStudy (triciaal):

when helpmeplease134 is not helping you then you will learn more

OpenStudy (anonymous):

shes helped me just fine. thank you for your concern

OpenStudy (anonymous):

@triciaal Please refrain from insulting my intellect that way. It upsets me that you would be so rude as to say I am not helping. I am required to explain the process to them... My apologies for doing it differently than you would. And do you understand how to use the table now @themightygabbs

OpenStudy (anonymous):

Yes thank you, Should it be g(x) has a greater maximum value than f(x) then?

OpenStudy (anonymous):

Yes! Good job!

OpenStudy (anonymous):

Ah thank you!

OpenStudy (anonymous):

No problem! Glad to help with any future questions too

OpenStudy (anonymous):

Ah thanks! That was my last question but you were really helpful!

OpenStudy (anonymous):

Thanks again!

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